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Old 10-05-2008, 05:50 PM   #1 (permalink)
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Algebra Help

Anyone good with Algebra?

I have ten word problems I have to do for my homework in a Col Algebra class. I absoluty suck at word problems. Even though there is no time in my professional life I will need to solve these problems, its still part of my Degree Requirement.


Anyone want to help a brother out?

Problems are like this.

There were 320 tickets sold for a basketball game. The activity cardholders tickets cost 1.75 and the non-cardholders tickets cost $2.00. The total amount of money collected was 623.50. How many of each ticket were sold?
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Old 10-05-2008, 06:02 PM   #2 (permalink)
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theres multiple answers for the question.... if u do the math if u only sold 18 cardholder tickets that costs 31.5, so u do 623.50-31.5=592/2= 296 non-cardholder tickets sold... pretty much if u can get the number to an even ending with the cardholder tickets then u can just divide 2 evenly into whatever the balance is.... its been awhile for algebra for me but i think im correct
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Old 10-05-2008, 06:07 PM   #3 (permalink)
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I figued it out.

The answer if figured out like this
x+y=320
1.75+2.00y=623.50
175+200y=62350

175(320-y)+200y=62300

So 254 Non ticket holders
and 66 ticket holders


ALGEBRA SUCKS, only nine more to go.

There were 321 tickets purchased for a major league baseball game. The lower reserved tickets cost 9.50 and the upper reserved tickets cost $8.00. The total amount of money spent was 2857.50. How many of each kind of ticket were purchased?
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Old 10-05-2008, 06:13 PM   #4 (permalink)
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oh..... im an idiot i skipped over the number of tickets part lol....
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Old 10-05-2008, 06:14 PM   #5 (permalink)
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hmmm, guess I am better at this than I think. The answer for that one is
x+y=321
9.50x+8.00y=2857.50
950x+800y=285750
950(321-y)+800y=285750
y=128
321-128=x
x=193
193 Lower tickets
128 Upper tickets


Eh, when the fuck will people ever actually use this shit. Algebra is crap.
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Old 10-05-2008, 06:14 PM   #6 (permalink)
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If you have 320 tickets sold, you will have 66 card holders (66x1.75=115.5) and 254 non-card holders (254x2.00=508). This adds up for all totals.
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Old 10-05-2008, 06:17 PM   #7 (permalink)
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One canned juice drink is 15% orange juice, another is 5% orange juice. HOw many liters of each should be mixed together in order to get 10L that is 10% orange juice?

This one sucks...........

Last edited by vlipke; 10-05-2008 at 06:26 PM.
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Old 10-05-2008, 06:46 PM   #8 (permalink)
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btw my answer came from IonTop and his friend Red....Im horrible at math and he Top is here tonight
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Old 10-05-2008, 06:52 PM   #9 (permalink)
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Quote:
Originally Posted by mrphoto103 View Post
btw my answer came from IonTop and his friend Red....Im horrible at math and he Top is here tonight

I stopped for tonight, couldnt figure out the one above.......

I need to do eight more problems like that, and it takes me forever to figure it out....fuck algebra......no point in knowing it....
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Old 10-05-2008, 06:53 PM   #10 (permalink)
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Quote:
Originally Posted by mrphoto103 View Post
btw my answer came from IonTop and his friend Red....Im horrible at math and he Top is here tonight
thanks.................


might just pay someone to finish the class for me...........LOL, its all online....
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